Contoh Soal Penyelesaian Tegangan, Arus, dan Tahanan


3. a.) Diket       :     R1= 60Ω                           I= 4mA
   R2= 1,2K Ω                  R3= 2,74KΩ               
          Ditanya   :   E = …?
          Jawab               :  RT = R1+R2+R3
                           = 60Ω+1,2K Ω+2,74KΩ
                           = 4000Ω
                               E = I.R
                                  = 0,004A.4KΩ  = 16 V
   b.)  Diket       :   R1= 1,2 Ω                      I= 250mA = 0,250A
                             R2= 8,2 Ω                      R3= 4,7 Ω            R4= 2,7 Ω
          Ditanya   :   E=…?
           Jawab     :  RT  = R1+R2+R3+R4
                                  = 1,2 Ω+8,2 Ω+4,7 Ω+2,7 Ω
                                  = 16,8 Ω
                             E = I.R= 0,250A.16,8 Ω  = 4,2 V
4. a.) Diket         : R1= 5 Ω     RT  = 16 Ω
                             R2 = 2 Ω    VR2 = 12 V
         Ditanya    :  a.) R3 = …?
                             b.) IR2 = ...?           c.) E  = ...?
Jawab                :  a.) R3 = RT –(R1+R2)
                             = 16 Ω -(5 Ω+2 Ω)
                             = 16 Ω - 7 Ω
                              = 9 Ω
                   b.) IR2 = V
                                         R2
                             =  12 V
                                  2 Ω
=  6 A
                   c.) E = VR1+VR2 +VR3                                         VR1 = I.R1
                           =         30V+12V+54V                             = 6A.5Ω  
                           = 96V                                               = 30 V
                                                                             VR3 = I.R2
                                                                                    = 6A.9 Ω
                                                                                    = 54 V
b.) Diket       :       R1= 3,3K Ω                            VR2 = 9V
                                      R3= 2,2K Ω                            PR3 = 79,2 mW
                Ditanya : a.) I R3 = …?
                               b.) R2= …?
                               C.) E= …?
                Jawab   :  a.) PR3 = I2.R                                                     
                                    IR3     =    PR3
                                                                                   R3
                                           =      79,2 mW
                                                     2,2K Ω
                                           =     36mA      
                                           = 6 mA
                               b.) R2 = VR2                                                           
                                              IR2
                                                                   =   9 V     = 1500 Ω
                                             0,006A
                                c.) E = VR1+VR2 +VR3                                    VR1 = I.R1
                                       = 19,8V+9V+13,2V                      = 0,006A.3,3K Ω
                                       =  42 V                                          = 19,8 V
                                                                                      PR3 = VR3.I
                                                                                      VR3 = PR3
                                                                                                                                                                  I
                                                                                      VR3=   79,2mW
                                                                                                 0,006A
                                                                                            = 13,2 V
5. a.) Diket       :   E1 = 8V               R1 = 4,7 Ω
                             E2 = 16V             R2 = 5,6 Ω           E3 = 4V
         Ditanya   :   I =…?                                     
         Jawab              :     RT =  R1+R2                                     
                                  = 4,7 Ω+5,6Ω = 10,3 Ω                                        
                             I =   ET                                                             ET = +16V-8V-4V
                                                              RT                                                                   = 4V
                               =    4V      = 0,388A
                                   10,3 Ω           
     b.) Diket       :  E1= 4V                          R1= 4,7 Ω
                             E2= 18V                        R2=1,2 Ω
                             E3= 10V                        R3= 5,6 Ω
          Ditanya   :   I = …?
          Jawab              :    RT = R1+R2         +R3                                ET = +E2+E3-E1
                                  = 4,7 Ω+1,2 Ω+5,6 Ω                                 =18V+10V-4V
                                  = 11,5 Ω                                                     =24V
                            

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